删除:

1 public int  RemoveAt( int indexOf) 2         { 3             int deleteDate=default(int); 4             if (indexOf >= _count || indexOf < 0) 5             { 6                 Console.WriteLine("出错!!!"); 7                 goto xt; 8             } 9             node temp = _head;10             for (int i = 0; i < indexOf; i++)11             {12                 temp = temp.Next;13             }     //现在temp为indexof前一个节点14                 node tibuNode = temp.Next;                  //连接链,关键操作!!!!!!15                 temp.Next = temp.Next.Next;                //将下标为indexof的节点连接到null,很重要!!!!!!!16                 tibuNode.Next = null;17                 _count--;      18                 return tibuNode.Date;19             xt:20                 return deleteDate;21         }

遍历:

1 //定义:第一个int为下标,第二个int为节点的date 若改为泛型改第二个int为T 2         public void ShowItem(Action
     
       ac) 3         { 4             if (_count == 0) 5             { 6                 Console.WriteLine("null"); 7                 return; 8             } 9             node temp = _head;10             for (int i = 0; i < _count; i++)11             {              12                 ac(i,temp.Date);13                 temp = temp.Next;14             }15         }16             //委托的方法17         public static void Show(int m, int Date)18         {19             Console.WriteLine("第{0}个元素是{1}",m,Date);20         }